ソースを参照

Small random corrections.

Michele Orrù 11 年 前
コミット
1cd881d8bf
共有2 個のファイルを変更した6 個の追加6 個の削除を含む
  1. 2 2
      book/dixon.tex
  2. 4 4
      book/pollardrho.tex

+ 2 - 2
book/dixon.tex

@@ -46,7 +46,7 @@ that $\mod{N}$ is equivalent to:
 \end{align}
 \end{align}
 and voil\`a our congruence of squares (\cite{discretelogs} \S 4). For what
 and voil\`a our congruence of squares (\cite{discretelogs} \S 4). For what
 concerns the generation of $x_i$ with the property \ref{eq:dixon:x_sequence},
 concerns the generation of $x_i$ with the property \ref{eq:dixon:x_sequence},
-they can simply taken at random and tested using trial division.
+they can simply be taken at random and tested using trial division.
 
 
 \paragraph{Brillhart and Morrison} later proposed (\cite{morrison-brillhart}
 \paragraph{Brillhart and Morrison} later proposed (\cite{morrison-brillhart}
 p.187) a better approach than trial division to find such $x$. Their idea aims
 p.187) a better approach than trial division to find such $x$. Their idea aims
@@ -222,7 +222,7 @@ $e^{\sqrt{\ln N \ln \ln N}}$.
     \Comment finding linearity requires redundance
     \Comment finding linearity requires redundance
     \While{$i < r$}
     \While{$i < r$}
     \Comment search for suitable pairs
     \Comment search for suitable pairs
-    \State $x_i \getsRandom \{0, \ldots N\}$
+    \State $x_i \getsRandom \naturalN_{< N}$
     \State $y_i \gets x_i^2 - N$
     \State $y_i \gets x_i^2 - N$
     \State $v_i \gets \texttt{smooth}(y_i)$
     \State $v_i \gets \texttt{smooth}(y_i)$
     \If{$v_i$} $i \gets i+1$ \EndIf
     \If{$v_i$} $i \gets i+1$ \EndIf

+ 4 - 4
book/pollardrho.tex

@@ -58,10 +58,10 @@ factor of $N$.
 \paragraph{Choosing the function} Ideally, $F$ should be easily computable, but
 \paragraph{Choosing the function} Ideally, $F$ should be easily computable, but
 at the same time random enough to reduce as much as possible the epacts
 at the same time random enough to reduce as much as possible the epacts
 ~\cite{Crandall} \S 5.2.1. Any quadratic function $F(x) = x^2 + b$ should be
 ~\cite{Crandall} \S 5.2.1. Any quadratic function $F(x) = x^2 + b$ should be
-enough \footnote{
+enough\footnote{
   Note that this has been only empirically verified, and so far not been proved
   Note that this has been only empirically verified, and so far not been proved
-  (~\cite{riesel}, p. 177)}
-, provided that $b \in \naturalN \setminus \{0, 2\}$.
+  (~\cite{riesel}, p. 177)},
+provided that $b \in \naturalN \setminus \{0, 2\}$.
 For example, ~\cite{pollardMC} uses $x^2 -1$, meanwhile we are going to choose
 For example, ~\cite{pollardMC} uses $x^2 -1$, meanwhile we are going to choose
 $F(x) = x^2 + 1$.
 $F(x) = x^2 + 1$.
 
 
@@ -150,7 +150,7 @@ this algorithm, based on the birthday paradox.
 
 
 We can obviously substitute the $365$ with any set of cardinality $\zeta$
 We can obviously substitute the $365$ with any set of cardinality $\zeta$
 to express the probability that a random function from $\integerZ_{\epsilon}$
 to express the probability that a random function from $\integerZ_{\epsilon}$
-to $\integerZ_{\zeta}$ is injective. Back to our particular case,
+to $\integerZ_{\zeta}$ is injective. However, back to our particular case,
 we want to answer the question:
 we want to answer the question:
 
 
 \emph{
 \emph{