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Fixing fermat's limit, and random.

Michele Orrù il y a 11 ans
Parent
commit
31e53e1c0e
3 fichiers modifiés avec 3 ajouts et 6 suppressions
  1. 1 1
      book/fermat.tex
  2. 2 0
      book/pollard+1.tex
  3. 0 5
      book/question_authority.tex

+ 1 - 1
book/fermat.tex

@@ -97,7 +97,7 @@ should be different between the two primes:
   \\
 %  \bitheader{}
   \\[1px]
-  \begin{rightwordgroup}{$2^{\log{\frac{N}{2}}-100}$}
+  \begin{rightwordgroup}{$2^{\frac{\log N}{2}-100}$}
     \bitbox{1}{0} & \bitbox{1}{0} & \bitbox{1}{0} & \bitbox{1}{0} &
     \bitbox{1}{0} & \bitbox{1}{0} & \bitbox{1}{0} & \bitbox{1}{0} &
     \bitbox{3}{\tiny $\cdots$} &

+ 2 - 0
book/pollard+1.tex

@@ -14,6 +14,8 @@ the application of this method to a large number of composite numbers.
   Nevertheless, there is no further information about the way the two
   factorization have been benchmarked.
 \end{remark}
+
+
 %%% Local Variables:
 %%% mode: latex
 %%% TeX-master: "question_authority"

+ 0 - 5
book/question_authority.tex

@@ -25,17 +25,12 @@
 \usepackage{supertabular}
 \usepackage{tikz}
 
-\usetikzlibrary{arrows}
-
 %% setting epigraphs
 \renewcommand{\epigraphsize}{\small}
 \setlength{\epigraphwidth}{0.8\textwidth}
 \let\origepigraph\epigraph
 \renewcommand\epigraph[2]{\origepigraph{\textit{#1}}{\textsc{#2}}}
 
-\input xy
-\xyoption{all}
-
 %% bytefield shit
 \newcommand{\colorbitbox}[3]{%
 \rlap{\bitbox{#2}{\color{#1}\rule{\width}{\height}}}%